Dies ist eine alte Version des Dokuments!
Block 09 - Force on charges and electric field strength
Learning objectives
- Sketch the field lines of electric fields.
- Distinguish charge $Q$ (source) from electric field $\vec{E}$ (effect in space) and force $\vec{F}$ on a test charge $q$; use formula for Coulomb force with correct vector directions and units ($1~{\rm N/C}=1~{\rm V/m}$).
- Explain and apply the superposition principle for forces and fields from multiple charges.
- Describe and sketch field lines for single and multiple charges; relate line density to $|\vec{E}|$ and line direction to the force on a positive test charge.
- Classify fields as homogeneous (e.g., parallel-plate region) or inhomogeneous (e.g., point charge); state typical properties near conductors (perpendicular boundary, field-free interior in electrostatics).
- Compute $|\vec{E}|$ for a point charge (Coulomb force), identify $\varepsilon$ and check dimensions.
- Determine the force on a charge in an electrostatic field by applying Coulomb's law. Specifically:
- The force vector in coordinate representation
- The magnitude of the force vector
- The angle of the force vector
- The direction of the force
- Determine a force vector by superimposing several force vectors using vector calculus.
90-minute plan
- Warm-up (8–10 min):
- Quick recall quiz: units of $Q$, $\vec{E}$, $\vec{F}$; passive sign convention for forces on a positive test charge.
- Dimensions check: show $1~{\rm N/C}=1~{\rm V/m}$.
- Concept build & demonstrations (35–40 min):
- Cause–field–effect chain: charges $\Rightarrow \vec{E}(\vec{x}) \Rightarrow \vec{F}=q\,\vec{E}$.
- Coulomb law $\Rightarrow$ point-charge field magnitude and direction.
- Superposition for two/three charges; vector addition.
- Field lines: definition, drawing rules, sources/sinks, no intersections; relate density to magnitude.
- Homogeneous vs. inhomogeneous fields; conductor boundary facts (perpendicular $\vec{E}$, interior field-free).
- Guided simulations (20–25 min)
- Practice (10–15 min):
- Short worksheet: sketch field lines for two like charges and a dipole; compute $|\vec{E}|$ at a marked point.
- Wrap-up (5 min):
- Summary map: charges → $\vec{E}$ → $\vec{F}$; key properties and units; preview link to equipotentials and energy (next block).
Conceptual overview
- Fields separate cause and effect: charges set up a state in space (the field) that exists whether or not a test charge is present.
- The electric field is a vector field $\vec{E}(\vec{x})$; its direction is the direction of the force on a *positive* test charge; its magnitude is given by the actinv force and the charge with units $1~{\rm N/C}=1~{\rm V/m}$.
- Point charge model: inverse-square law; direction is radial, outward for $Q>0$, inward for $Q<0$.
- Superposition holds: for multiple sources, $\vec{E}_{\rm total}=\sum_k \vec{E}_k$ (vector sum at the same point).
- Field lines visualize $\vec{E}$: start at $+$, end at $-$, never intersect; higher line density ⇔ larger $|\vec{E}|$; lines are not particle trajectories.
- Homogeneous fields (ideal between large parallel plates): parallel, equally spaced lines; inhomogeneous fields elsewhere (e.g., point charges, edges).
- Conductors (electrostatics): $\vec{E}$ is perpendicular to the surface; interior is field-free; surface charge arranges to enforce these conditions.
Core content
Electric Effects
Every day life teaches us that there are various charges and their effects. The image Abbildung 1 depicts a chargeable body that can be charged through charge separation between the sole and the floor. The movement of the foot generates a negative surplus charge in the body, which progressively spreads throughout the body. A current can flow even through the air if a pointed portion of the body (e.g., a finger) is brought into close proximity to a charge reservoir with no extra charges.
First, we shall define certain terms:
- Electricity is a catch-all term for any occurrences involving moving and resting charges.
- Electrostatics is the study of charges at rest and consequently electric fields that do not vary over time. As a result, the electrical quantities have no temporal dependence.
For any function of the electric quantities, ${{{\rm d} f}\over{{\rm d} t}}=0$ holds mathematically. - Electrodynamics describes the behavior of moving charges. Hence, electrodynamics covers both changing electric fields and magnetic fields.
For the time being, the simple explanation will be that magnetic fields are dependent on current or charge flow.
It is no longer true in electrodynamics that the derivative is always necessary for any function of electric values.
Only electrostatics is discussed in this chapter. For the time being, magnetic fields are thus excluded. Furthermore, electrodynamics is not covered in this chapter and is provided in further detail in subsequent chapters.
Fields
The concept of a field will now be briefly discussed in more detail.
- The introduction of the field distinguishes the cause from the effect.
- The field in space is caused by the charge $Q$.
- As a result of the field, the charge $q$ in space feels a force.
- This distinction is brought up again in this chapter.
It is also fairly obvious in electrodynamics at high frequencies: the field corresponds to photons, i.e. to a transmission of effects with a finite (light)speed $c$.
- There are different-dimensional fields, just like physical quantities:
- In a scalar field, each point in space is assigned a single number.
For example,- a temperature field $T(\vec{x})$ on a weather map or in an object
- a pressure field $p(\vec{x})$
- Each point in space in a vector field is assigned several numbers in the form of a vector. This reflects the action as it occurs along the spatial coordinates.
As an example.- gravitational field $\vec{g}(\vec{x})$ pointing to the object's center of mass.
- electric field $\vec{E}(\vec{x})$
- magnetic field $\vec{H}(\vec{x})$
- A tensor field is one in which each point in space is associated with a two- or more-dimensional physical quantity - that is, a tensor. Tensor fields are useful in mechanics (for example, the stress tensor), but they are not required in electrical engineering.
Vector fields are defined as follows:
- Effects along spatial axes $x$, $y$ and $z$ (Cartesian coordinate system).
- Effect in magnitude and direction vector (polar coordinate system)
educational Task
Place a negative charge $Q$ in the middle of the simulation and turn off the electric field. The latter is accomplished by using the hook on the right. The situation is now close to reality because a charge appears to have no effect at first glance.
A sample charge $q$ is placed near the existing charge $Q$ for impact analysis (in the simulation, the sample charge is called „sensors“). The charge $Q$ is observed to affect a force on the sample charge. At any point in space, the magnitude and direction of this force can be determined. In space, the force behaves similarly to gravity. A field serves to describe the condition space changed by the charge $Q$.
Abb. 2: setup for own experiments
Take a charge ($+1~{ \rm nC}$) and position it.
Measure the field across a sample charge (a sensor).
Note:
- Fields describe a physical state of space.
- Here, a physical quantity is assigned to each point in space.
- The electrostatic field is described by a vector field.
The electric Field
We had already considered the charge as the central quantity of electricity in block02 and recognized it as a multiple of the elementary charge. Now, we want to determine the electric field of charges. For this, a measurement of its magnitude and direction is now required. The Coulomb force between two charges $Q_1$ and $Q_2$ is:
\begin{align*} F_C = {{{1} \over {4\pi\cdot\varepsilon}} \cdot {{Q_1 \cdot Q_2} \over {r^2}}} \end{align*}
The force on a (fictitious) sample charge $q$ is now considered to obtain a measure of the magnitude of the electric field.
\begin{align*} F_C &= {{{1} \over {4\pi\cdot\varepsilon}} \cdot {{Q_1 \cdot q} \over {r^2}}} \\ &= \underbrace{{{1} \over {4\pi\cdot\varepsilon}} \cdot {{Q_1} \over {r^2}}}_\text{=independent of q} \cdot q \\ \end{align*}
As a result, the left part is a measure of the magnitude of the field, independent of the size of the sample charge $q$. Thus, the magnitude of the electric field is given by
$E = {{1} \over {4\pi\cdot\varepsilon}} \cdot {{Q_1} \over {r^2}} \quad$ with $[E]={{[F]}\over{[q]}}=1 ~{ \rm {N}\over{As}}=1 ~{ \rm {N\cdot m}\over{As \cdot m}} = 1 ~{ \rm {V \cdot A \cdot s}\over{As \cdot m}} = 1 ~{ \rm {V}\over{m}}$
The result is therefore \begin{align*} \boxed{F_C = E \cdot q} \end{align*}
The unit of $E$ is $\rm 1 {{N}\over{As}} = 1 {{V}\over{m}} $
Note:
- The test charge $q$ is always considered to be positive (mnemonic: t = +). It is only used as a thought experiment and has no retroactive effect on the sampled charge $Q$.
- The sampled charge here is always a point charge.
Note:
At a measuring point $P$, a charge $Q$ produces an electric field $\vec{E}(Q)$. This electric field is given by- the magnitude $|\vec{E}|=\Bigl| {{1} \over {4\pi\cdot\varepsilon}} \cdot {{Q_1} \over {r^2}} \Bigl| $ and
- the direction of the force $\vec{F_C}$ experienced by a sample charge on the measurement point $P$. This direction is indicated by the unit vector $\vec{e_{ \rm r}}={{\vec{F_C}}\over{|F_C|}}$ in that direction.
Be aware that in English courses and literature $\vec{E} $ is simply referred to as the electric field, and the electric field strength is the magnitude $|\vec{E}|$. In German notation, the Elektrische Feldstärke refers to $\vec{E}$ (magnitude and direction), and the Elektrische Feld denotes the general presence of an electrostatic interaction (often without considering exact magnitude).
The direction of the electric field is switchable in Abbildung 2 via the „Electric Field“ option on the right.
Direction of the Coulomb force and Superposition
In the case of the force, only the direction has been considered so far, e.g., direction towards the sample charge. For future explanations, it is important to include the cause and effect in the naming. This is done by giving the correct labeling of the subscript of the force. In Abbildung 3 (a) and (b), the convention is shown: A force $\vec{F}_{21}$ acts on charge $Q_2$ and is caused by charge $Q_1$. As a mnemonic, you can remember „tip-to-tail“ (first the effect, then the cause).
Furthermore, several forces on a charge can be superimposed, resulting in a single, equivalent force.
Strictly speaking, it must hold that $\varepsilon$ is constant in the structure. For example, the resultant force in Abbildung 3 Fig. (c) on $Q_3$ becomes equal to: $\vec{F_3}= \vec{F_{31}}+\vec{F_{32}}$.
Abbildung 3 Fig. (d) shows that for a charged surface, the force on a charge on top of this surface is always perpendicular to the surface itself.
Abb. 3: direction of coulomb force
.
Energy required to Displace a Charge in the electric Field
Now we want to see, whether we can derive the required energy to displace a charge in the electric field.
Since we know the force on a charge in an electrical field $\vec{E}$ (= Coulomb-Force $\vec{F}_C = q \cdot \vec{E} $), we can borrow some relationships from mechanics for the energy $\Delta W$:
\begin{align*} \Delta W = \int \vec{F} d\vec{r} = q \int \vec{E} d\vec{r} \end{align*}
Looks familiar? Maybe not on the first sight. But we already had defined the fraction of the energy difference per charge ${{\Delta W}\over{q}}$ as voltage $U$!
Therefore:
\begin{align*} \boxed{U = \int \vec{E} d\vec{r} } \end{align*}
We will apply this relationship in multiple of the upcoming blocks.
Common pitfalls
- Treating force and field as the same thing; forgetting $\vec{F}=q\,\vec{E}$ and the positive-test-charge convention.
- Mixing units (${\rm N}$, ${\rm C}$, ${\rm V}$, ${\rm m}$): not recognizing $1~{\rm N/C}=1~{\rm V/m}$.
- Drawing field lines as closed loops or allowing them to intersect (source field: start at $+$, end at $-$; no crossings).
- Ignoring vector addition in superposition (adding magnitudes instead of vectors).
- Assuming field exists only when a test charge is present; the field is a property of space due to sources.
- Using point-charge formulas too near extended objects; not identifying homogeneous vs. inhomogeneous regions.
- Forgetting conductor boundary facts: lines must be perpendicular to ideal conducting surfaces; interior $|\vec{E}|=0$ in electrostatics.
Exercises
Task 1.1.1 simple task with charges
Task 1.2.1 Multiple Forces on a Charge I (exam task, ca 8% of a 60-minute exam, WS2020)
Given is the arrangement of electric charges in the picture on the right.
The following force effects result:
$F_{01}=-5 ~\rm{N}$
$F_{02}=-6 ~\rm{N}$
$F_{03}=+3 ~\rm{N}$
Calculate the magnitude of the resulting force.
- How have the forces be prepared, to add them correctly?
The forces have to be resolved into coordinates. Here, it is recommended to use an orthogonal coordinate system ($x$ and $y$).
The coordinate system shall be in such a way, that the origin lies in $Q_0$, the x-axis is directed towards $Q_3$ and the y-axis is orthogonal to it.
For the resolution of the coordinates, it is necessary to get the angles $\alpha_{0n}$ of the forces with respect to the x-axis.
In the chosen coordinate system this leads to: $\alpha_{0n} = \arctan(\frac{\Delta y}{\Delta x})$
$\alpha_{01} = \arctan(\frac{3}{1})= 1.249 = 71.6°$
$\alpha_{02} = \arctan(\frac{4}{3})= 0.927 = 53.1°$
$\alpha_{03} = \arctan(\frac{0}{3})= 0= 0°$
Consequently, the resolved forces are:
\begin{align*} F_{x,0} &= F_{x,01} + F_{x,02} + F_{x,03} && | \quad \text{with } F_{x,0n} = F_{0n} \cdot \cos(\alpha_{0n}) \\ F_{x,0} &= (-5~\rm{N}) \cdot \cos(71.6°) + (-6~\rm{N}) \cdot \cos(53.1°) + (+3~\rm{N}) \cdot \cos(0°) \\ F_{x,0} &= -9.54 ~\rm{N} \\ \\ F_{y,0} &= F_{y,01} + F_{y,02} + F_{y,03} && | \quad \text{with } F_{y,0n} = F_{0n} \cdot \sin(\alpha_{0n}) \\ F_{y,0} &= (-5~\rm{N}) \cdot \sin(71.6°) + (-6~\rm{N}) \cdot \sin(53.1°) + (+3~\rm{N}) \cdot \sin(0°) \\ F_{y,0} &= -2.18 ~\rm{N} \\ \\ \end{align*}
Task 1.2.2 Variation: Multiple Forces on a Charge II (exam task, ca 8% of a 60 minute exam, WS2020)
Given is the arrangement of electric charges in the picture on the right.
The following force effects result:
$F_{01}=-5 ~\rm{N}$
$F_{02}=-6 ~\rm{N}$
$F_{03}=+3 ~\rm{N}$
Calculate the magnitude of the resulting force.
Task 1.2.3 Variation: Multiple Forces on a Charge II (exam task, ca 8% of a 60 minute exam, WS2020)
Given is the arrangement of electric charges in the picture on the right.
The following force effects result:
$F_{01}=+2 ~\rm{N}$
$F_{02}=-3 ~\rm{N}$
$F_{03}=+4 ~\rm{N}$
Calculate the magnitude of the resulting force.
Task 1.2.4 Superposition of Charges in 1D
Task 1.2.5 Forces on Charges (exam task, ca 8 % of a 60 minute exam, WS2020)
Given is an arrangement of electric charges located in a vacuum (see picture on the right).
The charges have the following values:
$Q_1=7 ~\rm{µC}$ (point charge)
$Q_2=5 ~\rm{µC}$ (point charge)
$Q_3=0 ~\rm{C}$ (infinitely extended surface charge)
$\varepsilon_0=8.854\cdot 10^{-12} ~\rm{F/m}$ , $\varepsilon_r=1$
1. calculate the magnitude of the force of $Q_2$ on $Q_1$, without the force effect of $Q_3$.
- Which equation is to be used for the force effect of charges?
- How can the distance between the two charges be determined?
2. is this force attractive or repulsive?
- What force effect do equally or oppositely charged bodies exhibit on each other?
Now let $Q_2=0$ and the surface charge $Q_3$ be designed in such a way that a homogeneous electric field with $E_3=100 ~\rm{kV/m}$ results.
What force (magnitude) now results on $Q_1$?
- Which equation is to be applied for the force action in the homogeneous field?
Task 1.2.6 Variation: Forces on Charges (exam task, ca 8% of a 60 minute exam, WS2020)
Given is an arrangement of electric charges located in a vacuum (see picture on the right).
The charges have the following values:
$Q_1=5 ~\rm{µC}$ (point charge)
$Q_2=-10 ~\rm{µC}$ (point charge)
$Q_3= 0 ~\rm{C}$ (infinitely extended surface charge)
$\varepsilon_0=8.854\cdot 10^{-12} ~\rm{F/m}$ , $\varepsilon_r=1$
1. calculate the magnitude of the force of $Q_2$ on $Q_1$, without the force effect of $Q_3$.
2. is this force attractive or repulsive?
Now let $Q_2=0$ and the surface charge $Q_3$ be designed in such a way that a homogeneous electric field with $E_3=500 ~\rm{kV/m}$ results.
What force (magnitude) now results on $Q_1$?
Task 1.2.7 Variation: Forces on Charges (exam task, ca 8% of a 60 minute exam, WS2020)
Given is an arrangement of electric charges located in a vacuum (see picture on the right).
The charges have the following values:
$Q_1= 2 ~\rm{µC}$ (point charge)
$Q_2=-4 ~\rm{µC}$ (point charge)
$Q_3= 0 ~\rm{C}$ (infinitely extended surface charge)
$\varepsilon_0=8.854\cdot 10^{-12} ~\rm{F/m}$ , $\varepsilon_r=1$
1. calculate the magnitude of the force of $Q_2$ on $Q_1$, without the force effect of $Q_3$.
2. is this force attractive or repulsive?
Now let $Q_2=0$ and the surface charge $Q_3$ be designed in such a way that a homogeneous electric field with $E_3=100 ~\rm{kV/m}$ results.
What force (magnitude) now results on $Q_1$?
Embedded resources
- Chapter 5. Electric Charges and Fields
- Chapter 6. Gauss's Law
- Chapter 7. Electrical Potential
- Chapter 8. Capacitance
Intro into electric field