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Exercise 2.7.9 - Variation: Simplifying Circuits II (written exam task, approx 8% of a 60 minute written exam, WS2020)
Given is the adjoining circuit with
$R_1=10 \Omega$
$R_2=20 \Omega$
$R_3=5 \Omega$
1. determine the equivalent resistance $R_{eq}$ between A and B by summing the resistances.
\begin{align*}
R_{ges} &= \frac{20 \Omega \cdot 5 \Omega}{\frac{3}{2}\cdot 20 \Omega + 5 \Omega} = 2.858 \Omega \rightarrow 2.9 \Omega
\end{align*}
2. now let the voltage from A to B be: $U_{AB}=U_0= 10 V$. What is the current $I$?
\begin{align*}
I =\frac{10V}{2 \cdot 5 \Omega} = 1 A
\end{align*}