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| Beide Seiten der vorigen Revision Vorhergehende Überarbeitung Nächste Überarbeitung | Vorhergehende Überarbeitung | ||
| electrical_engineering_and_electronics_1:block08 [2025/10/20 01:02] – mexleadmin | electrical_engineering_and_electronics_1:block08 [2025/10/24 20:35] (aktuell) – mexleadmin | ||
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| - | ====== Block 08 — Two-port theory and transforms ====== | + | ====== Block 08 — Two-terminal |
| < | < | ||
| Zeile 10: | Zeile 10: | ||
| On the {{https:// | On the {{https:// | ||
| + | ===== Learning objectives ===== | ||
| < | < | ||
| + | * Define **terminal** and **port**; distinguish **one-port** (two-terminal) vs. **two-port** views; identify input/ | ||
| + | * Apply **source transformations** between a voltage source with series $R$ and a current source with parallel $R$ using $U_0=I_0\, | ||
| + | * Construct **Thevenin** and **Norton** equivalents seen at a port: find $U_{\rm oc}$, $I_{\rm sc}$, and $R_{\rm i}$ by deactivating sources; relate $U_{\rm Th}=U_{\rm oc}$, $R_{\rm Th}=R_{\rm i}$, $I_{\rm No}=I_{\rm sc}$. | ||
| + | * Use the **superposition principle** to compute branch currents/ | ||
| + | * Combine transforms to reduce complex resistive networks to an **unloaded / loaded divider** and to size $R_{\rm L}$ for given performance goals (tie-in to Block 07 figures). | ||
| + | </ | ||
| - | * recap | + | ~~PAGEBREAK~~ ~~CLEARFIX~~ |
| - | * two-pole theory | + | ===== Preparation at Home ===== |
| - | * superposition | + | |
| + | And again: | ||
| + | * Please read through the following chapter. | ||
| + | * Also here, there are some clips for more clarification under ' | ||
| + | |||
| + | For checking your understanding please do the following exercise: | ||
| + | * 4.5.3 | ||
| - | ===== Learning objectives ===== | ||
| - | < | ||
| - | * Define / Distinguish / Apply / Use ... | ||
| - | </ | ||
| ===== 90-minute plan ===== | ===== 90-minute plan ===== | ||
| - | - Warm-up (5–10 | + | - Warm-up (8 min): |
| - | - Recall / Quick quiz ... | + | - Quick quiz on passive/ |
| - | - Core concepts & derivations (60–70 | + | - Identify ports and choose measurement directions on 2–3 small circuits. |
| - | - ... | + | - Core concepts & derivations (58 min): |
| - | - Practice (10–20 min): ... | + | - (1) **Source transformations** ($U_0\leftrightarrow I_0$, shared $R$), permissible assumptions, |
| - | - Wrap-up (5 min): ... | + | - (2) **Thevenin/ |
| + | - (3) **Superposition method**: deactivate sources, compute partial results, sum; worked DC example (15 min). | ||
| + | - Practice (20 min): | ||
| + | - Pair exercise set: reduce a 3-source network to Thevenin, then find $U_{\rm L}$, $I_{\rm L}$. | ||
| + | - Wrap-up (5 min): | ||
| + | - Summary table (when to use which method); minute paper: “One thing I can now do, one question I still have.” | ||
| ===== Conceptual overview ===== | ===== Conceptual overview ===== | ||
| <callout icon=" | <callout icon=" | ||
| - | - ... | + | - **Port thinking:** Draw a virtual cut around the “rest of the world”. At that boundary (two terminals), everything inside looks like an equivalent **linear source** (Thevenin/ |
| + | - **Source transformations: | ||
| + | - **Thevenin/ | ||
| + | - Open-circuit the load → measure/ | ||
| + | - Short the load (only if safe/valid) → $I_{\rm sc}=I_{\rm No}$. | ||
| + | - Deactivate sources → compute the internal resistance $R_{\rm i}=R_{\rm Th}=R_{\rm No}$. | ||
| + | - **Superposition (linear networks only):** Voltages and currents **add**; powers do **not**. For each source: deactivate the others (ideal $U$-sources → short; ideal $I$-sources → open), solve the partial, then sum with signs. | ||
| + | - **Choosing a method:** Use source transforms for quick topology changes, Thevenin/ | ||
| </ | </ | ||
| Zeile 39: | Zeile 60: | ||
| ===== Core content ===== | ===== Core content ===== | ||
| - | ==== 1st sub-chapter | + | ==== Two-Terminal Theory / One-Port Theory |
| + | |||
| + | <WRAP right> < | ||
| + | |||
| + | In order to understand the two-terminal theory / one-port theory, we first have to understand what a Terminal and port is. \\ | ||
| + | So, have a look to <imgref imageNo1>: | ||
| + | - A terminal or pole is simply an (imaginary or real) connector. This is shown in the diagram by a filled circle on one wire, plus a semicircle on the other wire | ||
| + | - A port is given by two terminals | ||
| + | |||
| + | But, how could this help us in simplifying circuits? \\ | ||
| + | Well: Usually, the voltage over or the current into one component or a group of component has to be found. \\ | ||
| + | Now, it is practical, that | ||
| + | * you can substitue every passive linear part (= consisting only of resistors) by a single equivalent resistor. | ||
| + | * you can substitue every active linear part (= consisting of resistors and sources) by a single equivalent linear source. | ||
| + | |||
| + | A linear part is here a cirucit consisting of linear components. | ||
| + | In general, ohmic resistors, sources, capacitors and inductors are linear - here, we only look onto resistors. (non-linear are most of the semiconductor components, like diodes). | ||
| + | |||
| + | So, what can we do? | ||
| + | Once you search for a distinct voltage or current: | ||
| + | - Imagine a virtual cut around this part. You get a passive linear part and a active linear part. | ||
| + | - Calculate the single equivalent resistor and single equivalent linear source. You get an unloaded voltage divider. | ||
| + | - Calculate the voltage divider | ||
| + | |||
| + | Voilà, we have a way to find our desired voltage or current in a complicated circuitry. | ||
| + | |||
| + | ~~PAGEBREAK~~ ~~CLEARFIX~~ <callout icon=" | ||
| + | There is a trick to get the internal resistance of the source easily, so without continuous back-and-forth beween linear voltage source and linear current source: | ||
| + | |||
| + | When one is only interested in the resistance of a complex circuit, do as follows: | ||
| + | - substitute every ideal source with its internal resistance (ideal voltage source → short circuit, ideal current source → unconnected). | ||
| + | - calculate the eqivalent resistance by means of series and parallel sub-circuits. | ||
| + | </ | ||
| - | ... | ||
| ==== Superposition Principle ==== | ==== Superposition Principle ==== | ||
| Zeile 106: | Zeile 158: | ||
| ~~PAGEBREAK~~ ~~CLEARFIX~~ | ~~PAGEBREAK~~ ~~CLEARFIX~~ | ||
| - | |||
| - | ==== n'th sub-chapter ==== | ||
| - | |||
| - | ... | ||
| - | |||
| ===== Common pitfalls ===== | ===== Common pitfalls ===== | ||
| - | * ... | + | * **Deactivating sources incorrectly: |
| - | ... | + | * **Superposing powers:** only **$u$** and **$i$** superpose; $P$ does not. Compute powers **after** summing. |
| + | | ||
| + | * **Sign/ | ||
| + | * **Applying linear methods to non-linear/ | ||
| + | * **Ignoring loading:** using the unloaded divider ratio $\dfrac{R_2}{R_1+R_2}$ while a finite $R_{\rm L}$ is attached → systematic voltage error. | ||
| | | ||
| ===== Exercises ===== | ===== Exercises ===== | ||
| - | |||
| - | ==== Quick checks ==== | ||
| - | |||
| - | # | ||
| - | # | ||
| - | |||
| - | Here is a simple exercise ... | ||
| - | |||
| - | # | ||
| - | |||
| - | Here is the solution of the Exercise 1 | ||
| - | |||
| - | # | ||
| - | # | ||
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| - | # | ||
| - | # | ||
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| - | Here is another simple exercise ... | ||
| - | |||
| - | # | ||
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| - | Here is the solution of the Exercise 2 | ||
| - | |||
| - | # | ||
| - | # | ||
| ==== Longer exercises ==== | ==== Longer exercises ==== | ||
| Zeile 362: | Zeile 386: | ||
| </ | </ | ||
| - | <WRAP column half> | ||
| - | Here are the youtube resource 2 | ||
| - | {{youtube> | ||
| - | </ | ||
| - | |||
| - | ... | ||