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electrical_engineering_and_electronics_1:block04 [2025/10/10 21:37] – [Bearbeiten - Panel] mexleadminelectrical_engineering_and_electronics_1:block04 [2025/10/14 11:36] (aktuell) – [Parallel circuit of resistors] mexleadmin
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 As always:  As always: 
   * Please read through the following chapter.   * Please read through the following chapter.
-  * Also here, three are some clips for more clarification under 'Embedded resources' (check the text above/below, sometimes only part of the clip is interesting). +  * Also here, there are some clips for more clarification under 'Embedded resources' (check the text above/below, sometimes only part of the clip is interesting). 
  
 For checking your understanding please do the following exercises: For checking your understanding please do the following exercises:
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 </WRAP> </WRAP>
  
-Since the same voltage $U_{ab}$ is dropped across all resistors, using Kirchhoff's current law:+Since the same voltage $U_{\rm ab}$ is dropped across all resistors, using Kirchhoff's current law:
  
-$\large{{U_{ab}}\over{R_1}}+ {{U_{ab}}\over{R_2}}+ ... + {{U_{\rm ab}}\over{R_n}}= {{U_{\rm ab}}\over{R_{\rm eq}}}$+$\large{{U_{\rm ab}}\over{R_1}}+ {{U_{\rm ab}}\over{R_2}}+ ... + {{U_{\rm ab}}\over{R_n}}= {{U_{\rm ab}}\over{R_{\rm eq}}}$
  
 $\rightarrow \large{{{1}\over{R_1}}+ {{1}\over{R_2}}+ ... + {{1}\over{R_n}}= {{1}\over{R_{\rm eq}}} = \sum_{x=1}^{n} {{1}\over{R_x}}}$ $\rightarrow \large{{{1}\over{R_1}}+ {{1}\over{R_2}}+ ... + {{1}\over{R_n}}= {{1}\over{R_{\rm eq}}} = \sum_{x=1}^{n} {{1}\over{R_x}}}$