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Task 1.2.3 Variation: Multiple Forces on a Charge II (exam task, ca 8% of a 60 minute exam, WS2020)
Given is the arrangement of electric charges in the picture on the right.
The following force effects result:
$F_{01}=+2 N$
$F_{02}=-3 N$
$F_{03}=+4 N$
Calculate the magnitude of the resulting force.
Result
\begin{align*}
|F_0| &= \sqrt{ (2.12 N)^2 + (0.38 N)^2 } = 2.16 N \rightarrow 2.2 N\\
\end{align*}