Unterschiede
Hier werden die Unterschiede zwischen zwei Versionen angezeigt.
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| electrical_engineering_1:task_l9hubowt6x00b2h5_with_calculation [2023/04/03 13:51] – angelegt mexleadmin | electrical_engineering_1:task_l9hubowt6x00b2h5_with_calculation [Unbekanntes Datum] (aktuell) – gelöscht - Externe Bearbeitung (Unbekanntes Datum) 127.0.0.1 | ||
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| - | Two objects experience a charge increase per time. In the <imgref l9hubowt6x00b2h5_1> | ||
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| - | 1. Determine the currents $I_1$ and $I_2$ for the two objects from the $Q$-$t$-diagram <imgref BildNr3> and plot the currents into a new diagram. | ||
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| - | * Have a look how much increase $\Delta Q$ per time duration $\Delta t$ is there for each object. | ||
| - | * For this choose a distinct time period, e.g. between $0~\rm s$ and $20~\rm s$. | ||
| - | * The current is then given as the change in charge per time: $I= {{\Delta Q}\over{\Delta t}}$ | ||
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| - | 2. How can the current be determined, when the charge increase on an object changes non-linearly? | ||
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| - | A non-linear charge increase leads to a non-constant current. \\ | ||
| - | For a non-constant current, one has to use the time derivative of the charge $Q$ to get the current $I$. \\ | ||
| - | So, the formula $I= {{{\rm d} Q}\over{{\rm d} t}}$ has to be used instead of $I= {{\Delta Q}\over{\Delta t}}$. | ||
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