Preparation

Dies ist eine alte Version des Dokuments!

calculate fractions in fractions correct: \begin{align*} {{{A}\over{B}}\over{C}} \quad &\neq \quad {{A}\over{{B}\over{C}}} \\ {{{A}\over{B}}\over{C}} = {{A}\over{{B}\cdot{C}}} \quad &\neq \quad {{A}\over{{B}\over{C}}} = {{A\cdot C}\over{B}} \end{align*}
Rearrange fractions correct: based on $\beta = {{I_C}\over{I_B}}$ on cannot derive $I_B = {{\beta}\over{I_C}}$..

Do not miss the units. For physical properties these are not allowed to be neglected.
Check the units. e.g. $dB$ cannot be converted in $V$
Once multiple components with indices are given (e.g. $C_1$, $C_2$) write down the indices every time, except $C_1 = C_2$ is explicitely given.
Check your (mis)conceptions on impedances
- Check whether $Z$ or $\underline{Z}$ is needed in formulas: $Z=|\underline{Z}|\neq \underline{Z}$
- impedances are not (only) resistors, at least do not think of $R$ is given as $\underline{Z}$.
  For purely ohmic components the other way around is correct: $\underline{Z}=R$.
- However, impedances 'act' like ohmic resistors in formulars.
  E.g. for the series circuit: $R_{eq}=R_1+R_2+R_3+... \rightarrow \underline{Z}_{eq}=\underline{Z}_1+\underline{Z}_2+\underline{Z}_3+... $
circuits have to be closed, the following is not correct:

Do not miss out questions. Sometimes there is more than one answer required.
Please add your solution path. Once only a wrong final result is given the grading will be 0.
When you at least give the correct basic formula there is the chance that you can get at least some reward..

Do math right